Решите пожалуйста: log2(sinx)+log2(cosx)+1=0

log2(sinx)+log2(cosx)+1=0
log2(sinx cosx)+1=0,sinx>0, cosx>0
log2(sinx cosx) = -1
log2(sinx cosx) =log2 (1/2)
(sinx cosx) = (1/2)
SIN2X = 1
2X =pI/2 +2pIn
X =pI/4 +pIn
sinx>0, cosx>0
X=pI/4 +2pI*k, k €Z